In how many consecutive zeroes does the product of?
between 115 and 201, lets count the mutliples of 5 they are between 115 and 200, there are (200115)/5 +1 of them, thats 18. Of these 18, 4 are multiple of 5^2 (125,150,175,200) of these 4, 1 is a multpiple of 5^3 (125) Not going into detail why there are more than enough mutlples of 2;4;8 but there sure are. So your answer is 18+4+1=23